I appreciate both of your efforts dealing with the Volume of the moon, however volume has nothing to do with the claims that I originally made. It is simply obvious that a sphere will contain much more volume than a cube that fits inside of it. If you must compare volumes, then you should do it in a way that matches my original premise, namely that if you made a cube out of the moon, that New Jerusalem would be a slightly larger cube. I was dealing strictly with SIZE comparison not total volume.

I concede however, that when I did a comparison of the cube to cube volumes, that I see that my original premise proves to be false – and the New Jerusalem cube is smaller than the moon cube, as follows:

According to the previous calculation, the volume of New Jerusalem: 2,628,072,000 cubic miles.

But in order to do an accurate comparison, to match my premise, we need to find the volume of the maximum cube that could be created from the moon.

Using 2,160 miles as the diameter of the moon, we need to find the length of side of that cube: So 2*A^2 = 2160 * 2160 [4,665,600]

Dividing both sides of the equation by 2, we get: A^2 = 2,332,800.

We calculate the square root to find “A”.

Therefore the longest length of any side of a cubed moon would be 1,527.351 miles.

And the volume of the cubed moon would be: 1,527.351^3 = 3,563,006,058.064025 cubic miles

To make a new comparison of the 2 cubes I divided 2,628,072,000 by 3,563,006,058.1 giving me the result that the New Jerusalem cube is 73.76% the size of the cubed moon.

Please check my figures and make sure I have it right this time. Thanks!

Robert D. [Bob] Wilson

]]>Bob

]]>Since the New Jerusalem is described to be a cube, we can get its volume using the formula the volume of a cube: V = s ^ 3 where s is the measurement of the side of a cube. Using 1,380 miles as the value of s, we will get 2,628,072,000 cubic miles.

Since the shape of the moon is spherical, we can compute its volume using the formula for the volume of a sphere: V = (4/3) * PI * (r ^ 3) where r is the radius of the square. Using 2,160 miles as the diameter of the moon, we’ll get 1,080 miles as the radius. Using the formula (4/3) * (3.1416) * ((1080) ^ 3), we’ll get 5,276,681,626 cubic miles.

Since the compute volume of the New Jerusalem is smaller than that of the moon, we can conclude that the New Jerusalem will be smaller than the moon.

If we will make a round watermelon (with the white rind and the fleshy inner part removed) as our scale model of the moon, and then make a box as a scale model of the new Jerusalem, the box will fit inside the watermelon.

]]>What I find amazing is that your writing sounds so much like it could have been written by my character Sashi, from my “Earth -The Arena” series. She also has a mystical garden that she travels to in her mind. You’ve actually given me a clue as to what she will experience in the 2nd book of the series [not yet completed].

Bob

]]>R D Wilson [Bob] ]]>