The size of New Jerusalem vs the Moon.


THE SIZE OF NEW JERUSALEM VS SIZE OF THE MOON

According to WikiAnswers http://wiki.answers.com/Q/What_is_the_diameter_of_the_moon :
       “The diameter of the Earth’s Moon is about 2,160 miles. (3475 kilometers.)”

 

The size of the New Jerusalem is given in Revelations 21:16 “And the city lies foursquare, and the length is as large as the breadth: and he measured the city with the reed, twelve thousand furlongs. The length and the breadth and the height of it are equal.”

 

So first we must convert “furlongs” [Greek = “stadia” or “stadion”] into miles.

The margin for the “New American Standard Bible” says that one stadia is equal to approximately 600 feet.

The footnote in the “English Standard Version” makes the figures a little more accurate, stating: “About 1,380 miles; a stadion was about 607 feet or 185 meters” (page 1251)”

 

In the above passage, the City of New Jerusalem is therefore described as a CUBE, measuring 1,380 miles in each direction.

 

In order to find the diameter of New Jerusalem (say from the back lower right corner to the front top left corner of the Cube) it will take 2 steps: 1) first, we must determine the length of the diagonal of its base, and 2) then, we must use that figure to calculate the distance through the center of the cube.  That will give us the greatest “diameter” of the City.

 

1)      To find the measure of the diagonal of the Cube’s base we shall use the formula to determine the hypotenuse of a right handed triangle (A2 + B2 = C2).
So (1380 x 1380) + (1380 x 1380) = 3,808,800
And the square root of 3,808,800 = 1,951.61 miles, which I will round to 1,952 miles.

 

 

 

 

 

2)    To find the measure of the diagonal of the Cube we need to again find the hypotenuse of a right triangle. 
In this case the base of the triangle is our result from (1) above or 1,952 miles.
          So (1952 x 1952) = 3,810,304
The height of the Cube, as stated before is 1,380 miles.
          So (1380 x 1380) = 1,904,400
The diameter of the Cube is the square root of 5,714,704 [I.E., 3,810,304 + 1,904,400].
This comes out to a diameter of 2,390.54 miles.

 

 

 

 CONCLUSION: 

The diameter of New Jerusalem is 2,390.54 miles.

The diameter of the Moon is only 2,160 miles.

Therefore if you shaved off the roundness of our moon to make it a cube, it would be SMALLER than the City of God. The diameter of New Jerusalem is 230.54 miles LARGER!

 

This amazing difference is multiplied even more when you realize that, New Jerusalem is NOT a planet or moon, so we don’t live OUTSIDE on its surface, but in layers upon golden layers on the INSIDE.

 

What is the actual volume of the inside of that Heavenly Cube, which will some day be our Home?
To find this we need to multiply the length, width and height, so:
      1,3803 = 2,628,072,000 cubic miles.  

My friend, that is over 2.6 Billion [with a “B”] cubic miles of glorious space, where the Lamb is the Light and no sin or shadow of darkness can enter and crying and sickness and pain and death will never even be thought about!  That is room for a <<LOT>> of “mansions” [and quite a few bungalows, as well.]

 

Imagine what the reaction would be on earth if this glowing planet suddenly appeared in the sky above everyone’s heads.  To borrow an illustration from scifi’s Star Trek: The sheer size of this "space craft" would make a "Borg Cube" appear less threatening that a rubber ducky floating in a lukewarm bathtub!  I believe that it DOES show up at the end of the Tribulation time, at the same time as Christ appears: no wonder all of the rebellious peoples of earth flee to the caves and beg the rocks to fall on them to hide them from the face of Him who sits on the throne!

Revelations 6:15-17 "And the kings of the earth, and the great men, and the rich men, and the chief captains, and the mighty men, and every bondman, and every free man, hid themselves in the dens and in the rocks of the mountains; and said to the mountains and rocks, Fall on us, and hide us from the face of him that sitteth on the throne, and from the wrath of the Lamb: for the great day of his wrath is come; and who shall be able to stand?"

And where is that "Throne" located???  I think in New Jerusalem.

 

Do you have a bought and paid for reservation for a place in that City?  Jesus paid the price and offers you one for free!

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About Robert Dennis Wilson

Author, Poet, Avid Reader, Scroll Saw Artist, & Singer-Songwriter. Telecommuting programmer/report writer by day.
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5 Responses to The size of New Jerusalem vs the Moon.

  1. Pingback: God & Aliens | Hold the Line

  2. Rod Bruce says:

    I have calculated that by using the Attic stadion (plural “stadia”) of 185.2 metres as the unit used in Revelation 21, the resultant “cubic city” is 222.4 km in width. This forms a cube with a volume that is exactly half that of the Moon.

    • Rod & Manning,

      I appreciate both of your efforts dealing with the Volume of the moon, however volume has nothing to do with the claims that I originally made. It is simply obvious that a sphere will contain much more volume than a cube that fits inside of it. If you must compare volumes, then you should do it in a way that matches my original premise, namely that if you made a cube out of the moon, that New Jerusalem would be a slightly larger cube. I was dealing strictly with SIZE comparison not total volume.

      I concede however, that when I did a comparison of the cube to cube volumes, that I see that my original premise proves to be false – and the New Jerusalem cube is smaller than the moon cube, as follows:

      According to the previous calculation, the volume of New Jerusalem: 2,628,072,000 cubic miles.

      But in order to do an accurate comparison, to match my premise, we need to find the volume of the maximum cube that could be created from the moon.
      Using 2,160 miles as the diameter of the moon, we need to find the length of side of that cube: So 2*A^2 = 2160 * 2160 [4,665,600]
      Dividing both sides of the equation by 2, we get: A^2 = 2,332,800.
      We calculate the square root to find “A”.
      Therefore the longest length of any side of a cubed moon would be 1,527.351 miles.
      And the volume of the cubed moon would be: 1,527.351^3 = 3,563,006,058.064025 cubic miles

      To make a new comparison of the 2 cubes I divided 2,628,072,000 by 3,563,006,058.1 giving me the result that the New Jerusalem cube is 73.76% the size of the cubed moon.

      Please check my figures and make sure I have it right this time. Thanks!

      Robert D. [Bob] Wilson

  3. Manny Manlangit says:

    To compare the sizes of two objects, it is easier to just compare their volumes.

    Since the New Jerusalem is described to be a cube, we can get its volume using the formula the volume of a cube: V = s ^ 3 where s is the measurement of the side of a cube. Using 1,380 miles as the value of s, we will get 2,628,072,000 cubic miles.

    Since the shape of the moon is spherical, we can compute its volume using the formula for the volume of a sphere: V = (4/3) * PI * (r ^ 3) where r is the radius of the square. Using 2,160 miles as the diameter of the moon, we’ll get 1,080 miles as the radius. Using the formula (4/3) * (3.1416) * ((1080) ^ 3), we’ll get 5,276,681,626 cubic miles.

    Since the compute volume of the New Jerusalem is smaller than that of the moon, we can conclude that the New Jerusalem will be smaller than the moon.

    If we will make a round watermelon (with the white rind and the fleshy inner part removed) as our scale model of the moon, and then make a box as a scale model of the new Jerusalem, the box will fit inside the watermelon.

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